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0c6c13dd38
* license: update headers to IBM Corp. * `make proto` * update offset because source file changed Signed-off-by: Ryan Cragun <me@ryan.ec> Co-authored-by: Ryan Cragun <me@ryan.ec>
38 lines
1.6 KiB
JavaScript
38 lines
1.6 KiB
JavaScript
/**
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* Copyright IBM Corp. 2016, 2025
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* SPDX-License-Identifier: BUSL-1.1
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*/
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import commonPrefix from 'core/utils/common-prefix';
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import { module, test } from 'qunit';
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module('Unit | Util | common prefix', function () {
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test('it returns empty string if called with no args or an empty array', function (assert) {
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let returned = commonPrefix();
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assert.strictEqual(returned, '', 'returns an empty string');
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returned = commonPrefix([]);
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assert.strictEqual(returned, '', 'returns an empty string for an empty array');
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});
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test('it returns empty string if there are no common prefixes', function (assert) {
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const secrets = ['asecret', 'secret2', 'secret3'].map((s) => ({ id: s }));
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const returned = commonPrefix(secrets);
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assert.strictEqual(returned, '', 'returns an empty string');
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});
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test('it returns the longest prefix', function (assert) {
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const secrets = ['secret1', 'secret2', 'secret3'].map((s) => ({ id: s }));
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let returned = commonPrefix(secrets);
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assert.strictEqual(returned, 'secret', 'finds secret prefix');
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const greetings = ['hello-there', 'hello-hi', 'hello-howdy'].map((s) => ({ id: s }));
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returned = commonPrefix(greetings);
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assert.strictEqual(returned, 'hello-', 'finds hello- prefix');
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});
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test('it can compare an attribute that is not "id" to calculate the longest prefix', function (assert) {
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const secrets = ['secret1', 'secret2', 'secret3'].map((s) => ({ name: s }));
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const returned = commonPrefix(secrets, 'name');
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assert.strictEqual(returned, 'secret', 'finds secret prefix from name attribute');
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});
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});
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