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	Now that the other architecture-specific lib directories have been moved out of the top-level directory there's not much reason to have the '_generic' suffix on the common lib directory. Signed-off-by: Peter Tyser <ptyser@xes-inc.com>
		
			
				
	
	
		
			56 lines
		
	
	
		
			2.1 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
			
		
		
	
	
			56 lines
		
	
	
		
			2.1 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
/* Copyright (C) 1992, 1997 Free Software Foundation, Inc.
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   This file is part of the GNU C Library.
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   The GNU C Library is free software; you can redistribute it and/or
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   modify it under the terms of the GNU Library General Public License as
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   published by the Free Software Foundation; either version 2 of the
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   License, or (at your option) any later version.
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   The GNU C Library is distributed in the hope that it will be useful,
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   but WITHOUT ANY WARRANTY; without even the implied warranty of
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   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
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   Library General Public License for more details.
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   You should have received a copy of the GNU Library General Public
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   License along with the GNU C Library; see the file COPYING.LIB.  If not,
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   write to the Free Software Foundation, Inc., 59 Temple Place - Suite 330,
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   Boston, MA 02111-1307, USA.  */
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typedef struct {
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	long    quot;
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	long    rem;
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} ldiv_t;
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/* Return the `ldiv_t' representation of NUMER over DENOM.  */
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ldiv_t
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ldiv (long int numer, long int denom)
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{
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  ldiv_t result;
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  result.quot = numer / denom;
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  result.rem = numer % denom;
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  /* The ANSI standard says that |QUOT| <= |NUMER / DENOM|, where
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     NUMER / DENOM is to be computed in infinite precision.  In
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     other words, we should always truncate the quotient towards
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     zero, never -infinity.  Machine division and remainer may
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     work either way when one or both of NUMER or DENOM is
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     negative.  If only one is negative and QUOT has been
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     truncated towards -infinity, REM will have the same sign as
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     DENOM and the opposite sign of NUMER; if both are negative
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     and QUOT has been truncated towards -infinity, REM will be
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     positive (will have the opposite sign of NUMER).  These are
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     considered `wrong'.  If both are NUM and DENOM are positive,
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     RESULT will always be positive.  This all boils down to: if
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     NUMER >= 0, but REM < 0, we got the wrong answer.  In that
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     case, to get the right answer, add 1 to QUOT and subtract
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     DENOM from REM.  */
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  if (numer >= 0 && result.rem < 0)
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    {
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      ++result.quot;
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      result.rem -= denom;
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    }
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  return result;
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}
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