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fix: use resource definition's default namespace in omnictl get

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The namespace flag default ("default") prevented fallback to the resource definition's own DefaultNamespace, causing resources in other namespaces (e.g., ResourceDefinitions in "meta") to return empty results.

Signed-off-by: Oguz Kilcan <oguz.kilcan@siderolabs.com>
This commit is contained in:
Oguz Kilcan 2026-04-10 11:45:04 +02:00
parent 131bd3a6bc
commit ba80cf6ec2
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GPG Key ID: 372F271E3AD80BFC
1 changed files with 1 additions and 2 deletions
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3
client/pkg/omnictl/get.go
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@ -16,7 +16,6 @@ import (
"github.com/siderolabs/omni/client/pkg/client"
"github.com/siderolabs/omni/client/pkg/cosi/labels"
omniresources "github.com/siderolabs/omni/client/pkg/omni/resources"
"github.com/siderolabs/omni/client/pkg/omnictl/internal/access"
"github.com/siderolabs/omni/client/pkg/omnictl/output"
"github.com/siderolabs/omni/client/pkg/omnictl/resources"
@ -267,7 +266,7 @@ func createResourceRequest(
}
func init() {
getCmd.PersistentFlags().StringVarP(&getCmdFlags.namespace, "namespace", "n", omniresources.DefaultNamespace, "The resource namespace.")
getCmd.PersistentFlags().StringVarP(&getCmdFlags.namespace, "namespace", "n", "", "The resource namespace.")
getCmd.PersistentFlags().BoolVarP(&getCmdFlags.watch, "watch", "w", false, "Watch the resource state.")
getCmd.PersistentFlags().StringVarP(&getCmdFlags.output, "output", "o", "table", "Output format (json, table, yaml, jsonpath).")
getCmd.PersistentFlags().StringVarP(&getCmdFlags.selector, "selector", "l", "", "Selector (label query) to filter on, supports '=' and '==' (e.g. -l key1=value1,key2=value2)")