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BUG/MINOR: hlua: Fix memory leaks on error path when registering a fetch

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When an error occurred in hlua_register_fetches(), the allocated lua
function and keyword must be released to avoid memory leaks.

This patch depends on "MINOR: hlua: Add function to release a lua
function". It may be backported in all stable versions. It should fix #1112.
This commit is contained in:
Christopher Faulet 2021-04-12 14:11:50 +02:00
parent aa22430bba
commit 2567f18382
1 changed files with 11 additions and 5 deletions
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16
src/hlua.c
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@ -6820,7 +6820,7 @@ __LJMP static int hlua_register_fetches(lua_State *L)
int ref;
int len;
struct sample_fetch_kw_list *sfk;
struct hlua_function *fcn;
struct hlua_function *fcn = NULL;
struct sample_fetch *sf;
struct buffer *trash;
@ -6849,15 +6849,15 @@ __LJMP static int hlua_register_fetches(lua_State *L)
/* Allocate and fill the sample fetch keyword struct. */
sfk = calloc(1, sizeof(*sfk) + sizeof(struct sample_fetch) * 2);
if (!sfk)
WILL_LJMP(luaL_error(L, "Lua out of memory error."));
goto alloc_error;
fcn = new_hlua_function();
if (!fcn)
WILL_LJMP(luaL_error(L, "Lua out of memory error."));
goto alloc_error;
/* Fill fcn. */
fcn->name = strdup(name);
if (!fcn->name)
WILL_LJMP(luaL_error(L, "Lua out of memory error."));
goto alloc_error;
fcn->function_ref[hlua_state_id] = ref;
/* List head */
@ -6867,7 +6867,7 @@ __LJMP static int hlua_register_fetches(lua_State *L)
len = strlen("lua.") + strlen(name) + 1;
sfk->kw[0].kw = calloc(1, len);
if (!sfk->kw[0].kw)
return luaL_error(L, "Lua out of memory error.");
goto alloc_error;
snprintf((char *)sfk->kw[0].kw, len, "lua.%s", name);
sfk->kw[0].process = hlua_sample_fetch_wrapper;
@ -6882,6 +6882,12 @@ __LJMP static int hlua_register_fetches(lua_State *L)
sample_register_fetches(sfk);
return 0;
alloc_error:
release_hlua_function(fcn);
ha_free(&sfk);
WILL_LJMP(luaL_error(L, "Lua out of memory error."));
return 0; /* Never reached */
}
/* This function is a lua binding to set the wake_time.